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Grid Challenge

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205 Discussions

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  • daniel_alvarado2
     + 0 comments

    C#

    public static string gridChallenge(List grid) {

    List<string> arrangedGrid = new List<string>();

    foreach(string s in grid)
    {
        arrangedGrid.Add(new string(s.OrderBy(x=>x).ToArray()));

    }               

    for(int row = 0; row < arrangedGrid.Count - 1; row++)
    {
        for (int column = 0; column < arrangedGrid[0].Count(); column++)
        {
            if(arrangedGrid[row][column] > arrangedGrid[row + 1][column])
            {
                return "NO";
            }
        }
    }

    return "YES";

}

  • micheldejesus
     + 0 comments

    Java 

        public static String gridChallenge(List<String> grid) {
        int[][] values = new int[grid.size()][grid.get(0).length()];
        for (int i=0 ; i<grid.size() ; i++) {
            char[] chars = grid.get(i).toCharArray();
            Arrays.sort(chars);
            
            for (int j=0 ; j<chars.length ; j++) {
                values[i][j] = (int) chars[j];
                if (i > 0 && values[i-1][j] > values[i][j]) {
                     return "NO";
                }
            }     
        }
        return "YES";
    }

  • gillrodrigues_
     + 0 comments

    There is no way to run out of O(n²) because of the column's checking, but follow a O(n) way to sort each row's string, 

    function gridChallenge(grid) {
    for (let i = 0; i < grid.length; i++) {
        grid[i] = sortString(grid[i]);
    }
    let answer = 'YES';
    for (let idr = 1; idr < grid.length; idr++) {
        for (let idc = 0; idc < grid[0].length; idc++) {
            if (grid[idr][idc] < grid[idr-1][idc]) {
                answer = 'NO';
                break;
            }
        }
    }
    return answer;
}

function sortString(str) {
    const ALPHABET_SIZE = 26;
    const charCount = Array(ALPHABET_SIZE).fill(0);
    const asciiStartLowercase = "a".charCodeAt(0);

    for (const char of str) {
        charCount[char.charCodeAt(0) - asciiStartLowercase]++;
    }

    let sortedStr = "";
    for (let i = 0; i < charCount.length; i++) {
        if (charCount[i] > 0) {
            sortedStr += String.fromCharCode(i + asciiStartLowercase).repeat(charCount[i]);
        }
    }
    return sortedStr;
}

  • hcussen
     + 0 comments

    The question says that the grid will be square, yet some of the test cases (at least Test Case 1) have nonsquare grids. This is easy enough to resolve in the code, but the question wording is misleading.

  • terrymayone
     + 0 comments

    Here is one way to do it in javaScript

    function gridChallenge(grid) {
    // Write your code here
    const sortedGrid = grid.map(row => row.split('').sort().join(''))

    for(let col = 0; col < sortedGrid[0].length; col++){
        for(let row = 1; row < sortedGrid.length; row++){
            if(sortedGrid[row][col] < sortedGrid[row - 1][col]){
                return "NO"
            }
        }
    }

    return "YES"
}