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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Diagonal Difference
  5. Discussions

Diagonal Difference

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5846 Discussions

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  • nigelljama
     + 0 comments
    def diagonalDifference(arr):
    n = 0
    lr = 0
    rl = 0
    for x in arr:
        lr += x[n]
        n+=1 
    
    for x in arr:
        rl += x[n-1]
        n-=1 
    
    return lr - rl if lr - rl > 0 else (lr - rl) * -1

  • serenitydiver
     + 0 comments

    In Java i have solved in that way , sure there could be a better solution ` public static int diagonalDifference(List> arr) { int rowSize = arr.size();

        int ltrSum = 0;
    int rtlSum = 0;
    for(int i = 0; i < rowSize; i++) {
        ltrSum = ltrSum + arr.get(i).get(i);
        rtlSum = rtlSum + arr.get(i).get(rowSize - (i + 1));
    }

    return Math.abs(ltrSum - rtlSum);
}

    }

  • SVVBathini_w
     + 0 comments

    For Python3 Platform

    I wrote the code from scratch just to get more practice

    def diagonalDifference(arr):
    lr = rl = 0
    n = len(arr)
    for i in range(n):
        lr += arr[i][i]
        rl += arr[i][n-1-i]
    
    return abs(lr - rl)

n = int(input())
arr = []
for _ in range(n):
    arr.append(list(map(int, input().split())))


result = diagonalDifference(arr)

print(result)

  • sumyta
     + 0 comments

    let n = arr.length; let primarySum = 0; let secondarySum = 0;

    for (let i = 0; i < n; i++) {
    primarySum += arr[i][i];           
    secondarySum += arr[i][n - 1 - i]; 
}

return Math.abs(primarySum - secondarySum);

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     + 0 comments

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