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  1. Prepare
  2. Data Structures
  3. Stacks
  4. Balanced Brackets
  5. Discussions

Balanced Brackets

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1632 Discussions

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  • gauravvgaikwad07
     + 0 comments

    What's the issue?

    include

    using namespace std; void printstack(stack s){ while(!s.empty()){ cout< st; bool t=true; for (auto ch:s){ if ((ch=='(')||(ch=='[') || (ch=='{')){ st.push(ch); //printstack(st); }else{ if ((ch==')') && (st.top()=='(')){ st.pop(); }else if((ch==']') &&(st.top()=='[')){ st.pop(); }else if((ch=='}') && (st.top()=='{')){ st.pop(); }else{ return "NO"; } } }

    if (st.empty()){
    return "YES";
}else{
    return "NO";
}

    } int main(){ int t; cin>>t; while(t--){ string s; cin>>s; cout<

  • f97gp1
     + 0 comments

    I try a recursive solution just for fun (won't pass the test cases)

        # rest of the code ...
    # the methods are naive methods and self explained.
    # `stack` variable could be considered as a global variable.
    def isBalanced(self, s: str, stack: deque) -> bool:
        c: str = s[0]
        
        if self.isOpenBracket(c):
            stack.append(c)
        else:
            stack_top: str = stack.pop()
            if not self.areBothBracketsBalanced(stack_top, c):
                print('\tnot-match: ', stack_top, c)

                return False
            
            if len(s) == 1 and len(stack) == 0:
                print('\tfinal-case OK')
                
                return True
        
        # New solution.
        new_sol: str = s[1:]
        
        if len(new_sol) > 0:
            return self.isBalanced(new_sol, stack)

  • rajivaiyer
     + 0 comments

    Fairly simple Stack based problem. Nothing too complex.

    Here's my Java 8 solution, passing all test cases, for Max Score of 25:

    class Result {
    
    private static final String B_ROUND  = "()";
    private static final String B_SQUARE = "[]";
    private static final String B_CURLY  = "{}";
    
    private static String getBracketType(Character bracketCh) {
        return getBracketType("" + bracketCh);
    }
    
    private static String getBracketType(String bracketStr) {
        switch(bracketStr) {
            case "(":
            case ")":
                return B_ROUND;
            case "[":
            case "]":
                return B_SQUARE;
            case "{":
            case "}":
                return B_CURLY;
            default:
                return "";
        }
    }
    
    private static Character getExpectedOpenBracketCh(String curBracketType) {
        switch (curBracketType) {
            case B_ROUND:
                return '(';
            case B_SQUARE:
                return '[';
            case B_CURLY:
                return '{';
            default:
                return 'd';
        }
    }
    
    /*
     * Complete the 'isBalanced' function below.
     *
     * The function is expected to return a STRING.
     * The function accepts STRING s as parameter.
     */

    public static String isBalanced(String s) {
        // Write your code here
        Stack<Character> bracketsStack = new Stack<>();

        System.err.println(""); System.err.println("");
        System.err.println("s=" + s);

        for (int sIdx = 0 ; sIdx < s.length() ; sIdx++) {

            Character sCh = s.charAt(sIdx);
            String curBracketType = getBracketType(sCh);
            
            // System.err.println("sIdx=" + sIdx + " | sCh=" + sCh + " | " +
            //                    "curBracketType=" + curBracketType);

            switch(sCh) {
                case '(':
                case '[':
                case '{':
                    bracketsStack.push(sCh);
                    break;

                case ')':
                case ']':
                case '}':
                
                    if (bracketsStack.isEmpty()) {
                        return "NO";
                    }

                    Character peekStackTopBracket =
                                  bracketsStack.peek();

                    Character expectedOpenBracket = 
                                  getExpectedOpenBracketCh(curBracketType);
                                  
                    // System.err.println("peekStackTopBracket=" + 
                    //                    peekStackTopBracket + " | " +
                    //                    "expectedOpenBracket=" + 
                    //                    expectedOpenBracket);

                    if (peekStackTopBracket != expectedOpenBracket) {
                        return "NO";
                    }

                    bracketsStack.pop();
                    break;
            }
        }
        
        if (!bracketsStack.isEmpty()) {
            return "NO";
        }

        return "YES";
    }

}

  • yousefbahaa487
     + 0 comments

    C++: its run correctly in my compiler but when i run it on hackerrank it shows me that all test cases are wrong, and i try all of the test cases and it run correct on my compiler, i dont know what to do!!

    #include<bits/stdc++.h>
using namespace std;
void fastIO()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
}
int main()
{
    fastIO();
    int t;
    cin >> t;
    cin.ignore();
    
    while (t--) {
        stack<char>st;
        bool balanced= 1;
        string line;
        getline(cin, line);
        
        for (int i = 0; i < line.length(); i++)
        {
            if(line[i]=='('||line[i]=='{'||line[i]=='[') {
                st.push(line[i]);
            }
            else if(line[i]==')'||line[i]=='}'||line[i]==']')
            {
                if(!st.empty())
                {
                    if(line[i]==')'&&st.top()=='(')st.pop();
                    else if(line[i]==']'&&st.top()=='[')st.pop();
                    else if(line[i]=='}'&&st.top()=='{')st.pop();
                    else {
                        
                        balanced=0;
                        break; 
                    }
                }
            }
        }
        
        if(balanced==0||!st.empty()){
            cout<<"No"<<"\n";
            balanced=1;
        }
        else cout<<"Yes"<<"\n";
        
    }
    return 0;
}
        
    }
    return 0;
}

  • awadallayossef
     + 0 comments
    def isBalanced(s):
    closeToOpen = { ")" : "(", "]" : "[", "}" : "{" }
    Stack = []

    for x in s:
        if x in closeToOpen:
            if Stack and Stack[-1] == closeToOpen[x]:
                Stack.pop()
            else:
                return "NO"
        else:
            Stack.append(x)

    return "NO" if len(Stack) > 0 else "YES"